What is the integral of 1/(yln^3(y)) ?

The integral of 1/(yln^3(y)) is -1/(2ln^2(y))+C

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integral of 1/(yln^3(y))

\int \frac{1}{y ln ^{3} ( y )} d y

- \frac{1}{2 ln ^{2} ( y )} + C

Solution steps

\int \frac{1}{y ln ^{3} ( y )} d y

Apply u-substitution

: \int \frac{1}{u ^{3}} d u

= \int \frac{1}{u ^{3}} d u

Apply the Power Rule

: - \frac{1}{2 u ^{2}}

= - \frac{1}{2 u ^{2}}

Substitute back

u = ln (y)

= - \frac{1}{2 ln ^{2} ( y )}

Add a constant to the solution

= - \frac{1}{2 ln ^{2} ( y )} + C

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What is the integral of 1/(yln^3(y)) ?
The integral of 1/(yln^3(y)) is -1/(2ln^2(y))+C