What is the integral of 1/(sqrt(y)+5) ?

The integral of 1/(sqrt(y)+5) is 2(sqrt(y)+5-5ln|sqrt(y)+5|)+C

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integral of 1/(sqrt(y)+5)

\int \frac{1}{y + 5} d y

2 (y + 5 - 5 ln ∣ y + 5 ∣) + C

Solution steps

\int \frac{1}{y + 5} d y

Apply u-substitution

: \int \frac{2 ( u - 5 )}{u} d u

= \int \frac{2 ( u - 5 )}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{u - 5}{u} d u

Expand

\frac{u - 5}{u} : 1 - \frac{5}{u}

= 2 \cdot \int 1 - \frac{5}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int 1 d u - \int \frac{5}{u} d u)

\int 1 d u = u

\int \frac{5}{u} d u = 5 ln ∣ u ∣

= 2 (u - 5 ln ∣ u ∣)

Substitute back

u = y + 5

= 2 (y + 5 - 5 ln ∣ y + 5 ∣)

Add a constant to the solution

= 2 (y + 5 - 5 ln ∣ y + 5 ∣) + C

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What is the integral of 1/(sqrt(y)+5) ?
The integral of 1/(sqrt(y)+5) is 2(sqrt(y)+5-5ln|sqrt(y)+5|)+C