What is the integral of x^2(x^2-16)^{3/2} ?

The integral of x^2(x^2-16)^{3/2} is

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integral of x^2(x^2-16)^{3/2}

\int x^{2} (x^{2} - 16)^{\frac{3}{2}} d x

\frac{1}{3} x^{3} (x^{2} - 16)^{\frac{3}{2}} - 4096 (\frac{1}{24576} x^{5} (x^{2} - 16)^{\frac{1}{2}} - \frac{1}{6144} x^{3} (x^{2} - 16)^{\frac{1}{2}} - \frac{1}{256} x (x^{2} - 16)^{\frac{1}{2}} - \frac{3}{8} ln (\frac{1}{4} x + (x^{2} - 16)^{\frac{1}{2}}) + \frac{5}{16} ln (\frac{1}{4} x + (x^{2} - 16)^{\frac{1}{2}})) + C

Solution steps

\int x^{2} (x^{2} - 16)^{\frac{3}{2}} d x

Simplify

x^{2} : xx

= \int xx (x^{2} - 16)^{\frac{3}{2}} d x

Apply Integration By Parts

: \frac{1}{3} x^{3} (x^{2} - 16)^{\frac{3}{2}} - \int x^{4} (x^{2} - 16)^{\frac{1}{2}} d x

= \frac{1}{3} x^{3} (x^{2} - 16)^{\frac{3}{2}} - \int x^{4} (x^{2} - 16)^{\frac{1}{2}} d x

\int x^{4} (x^{2} - 16)^{\frac{1}{2}} d x = 4096 - \frac{1}{1024} x^{3} (x^{2} - 16)^{\frac{1}{2}} - \frac{3}{128} x (x^{2} - 16)^{\frac{1}{2}} + 16 ln \frac{( x ^{2} - 16 ) ^{\frac{1}{2}} + x}{4} + \frac{1}{24576} x^{5} (x^{2} - 16)^{\frac{1}{2}} + \frac{5}{6144} x^{3} (x^{2} - 16)^{\frac{1}{2}} + \frac{5}{256} x (x^{2} - 16)^{\frac{1}{2}} + \frac{5}{16} ln (\frac{1}{4} (x^{2} - 16)^{\frac{1}{2}} + x)

= \frac{1}{3} x^{3} (x^{2} - 16)^{\frac{3}{2}} - 4096 - \frac{1}{1024} x^{3} (x^{2} - 16)^{\frac{1}{2}} - \frac{3}{128} x (x^{2} - 16)^{\frac{1}{2}} + 16 ln \frac{( x ^{2} - 16 ) ^{\frac{1}{2}} + x}{4} + \frac{1}{24576} x^{5} (x^{2} - 16)^{\frac{1}{2}} + \frac{5}{6144} x^{3} (x^{2} - 16)^{\frac{1}{2}} + \frac{5}{256} x (x^{2} - 16)^{\frac{1}{2}} + \frac{5}{16} ln (\frac{1}{4} (x^{2} - 16)^{\frac{1}{2}} + x)

Simplify

\frac{1}{3} x^{3} (x^{2} - 16)^{\frac{3}{2}} - 4096 - \frac{1}{1024} x^{3} (x^{2} - 16)^{\frac{1}{2}} - \frac{3}{128} x (x^{2} - 16)^{\frac{1}{2}} + 16 ln \frac{( x ^{2} - 16 ) ^{\frac{1}{2}} + x}{4} + \frac{1}{24576} x^{5} (x^{2} - 16)^{\frac{1}{2}} + \frac{5}{6144} x^{3} (x^{2} - 16)^{\frac{1}{2}} + \frac{5}{256} x (x^{2} - 16)^{\frac{1}{2}} + \frac{5}{16} ln (\frac{1}{4} (x^{2} - 16)^{\frac{1}{2}} + x) : \frac{1}{3} x^{3} (x^{2} - 16)^{\frac{3}{2}} - 4096 (\frac{1}{24576} x^{5} (x^{2} - 16)^{\frac{1}{2}} - \frac{1}{6144} x^{3} (x^{2} - 16)^{\frac{1}{2}} - \frac{1}{256} x (x^{2} - 16)^{\frac{1}{2}} - \frac{3}{8} ln (\frac{1}{4} x + (x^{2} - 16)^{\frac{1}{2}}) + \frac{5}{16} ln (\frac{1}{4} x + (x^{2} - 16)^{\frac{1}{2}}))

= \frac{1}{3} x^{3} (x^{2} - 16)^{\frac{3}{2}} - 4096 (\frac{1}{24576} x^{5} (x^{2} - 16)^{\frac{1}{2}} - \frac{1}{6144} x^{3} (x^{2} - 16)^{\frac{1}{2}} - \frac{1}{256} x (x^{2} - 16)^{\frac{1}{2}} - \frac{3}{8} ln (\frac{1}{4} x + (x^{2} - 16)^{\frac{1}{2}}) + \frac{5}{16} ln (\frac{1}{4} x + (x^{2} - 16)^{\frac{1}{2}}))

Add a constant to the solution

= \frac{1}{3} x^{3} (x^{2} - 16)^{\frac{3}{2}} - 4096 (\frac{1}{24576} x^{5} (x^{2} - 16)^{\frac{1}{2}} - \frac{1}{6144} x^{3} (x^{2} - 16)^{\frac{1}{2}} - \frac{1}{256} x (x^{2} - 16)^{\frac{1}{2}} - \frac{3}{8} ln (\frac{1}{4} x + (x^{2} - 16)^{\frac{1}{2}}) + \frac{5}{16} ln (\frac{1}{4} x + (x^{2} - 16)^{\frac{1}{2}})) + C

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What is the integral of x^2(x^2-16)^{3/2} ?
The integral of x^2(x^2-16)^{3/2} is