What is the integral of (400x^2)/(sqrt(x^3+4600)) ?

The integral of (400x^2)/(sqrt(x^3+4600)) is 800/3 sqrt(x^3+4600)+C

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integral of (400x^2)/(sqrt(x^3+4600))

\int \frac{400 x ^{2}}{x ^{3} + 4600} d x

\frac{800}{3} x^{3} + 4600 + C

Solution steps

\int \frac{400 x ^{2}}{x ^{3} + 4600} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 400 \cdot \int \frac{x ^{2}}{x ^{3} + 4600} d x

Apply u-substitution

: \int \frac{2}{3} d u

= 400 \cdot \int \frac{2}{3} d u

Integral of a constant:

\int a d x = a x

= 400 \cdot \frac{2}{3} u

Substitute back

u = x^{3} + 4600

= 400 \cdot \frac{2}{3} x^{3} + 4600

Simplify

400 \cdot \frac{2}{3} x^{3} + 4600 : \frac{800}{3} x^{3} + 4600

= \frac{800}{3} x^{3} + 4600

Add a constant to the solution

= \frac{800}{3} x^{3} + 4600 + C

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What is the integral of (400x^2)/(sqrt(x^3+4600)) ?
The integral of (400x^2)/(sqrt(x^3+4600)) is 800/3 sqrt(x^3+4600)+C