What is the solution for y^2dx+x(x-y)dy=0 ?

The solution for y^2dx+x(x-y)dy=0 is y=-\W(-(c_{1})/x)x

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y^2dx+x(x-y)dy=0

y^{2} d x + x (x - y) d y = 0

y = - W (- \frac{c _{1}}{x}) x

Solution steps

y^{2} d x + x (x - y) d y = 0

Solve using substitution:

y = - W (- \frac{c _{1}}{x}) x

y = - W (- \frac{c _{1}}{x}) x

\int_{- 1}^{1} 2 x d x

2 t^{2} - 3 t + 3

x \to \infty lim (5 x^{4})

\frac{\frac{1}{s + 1} + \frac{3}{2}}{s + 2}

y^{^{''}} + 4 y^{^{'}} + 5 y = 35 e - 4 x, y (0) = - 6, y^{^{'}} (0) = 1

What is the solution for y^2dx+x(x-y)dy=0 ?
The solution for y^2dx+x(x-y)dy=0 is y=-\W(-(c_{1})/x)x