What is the integral of 4/(e^{-s)} ?

The integral of 4/(e^{-s)} is 4e^s+C

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integral of 4/(e^{-s)}

\int \frac{4}{e ^{- s}} d s

4 e^{s} + C

Solution steps

\int \frac{4}{e ^{- s}} d s

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{e ^{- s}} d s

Simplify

\frac{1}{e ^{- s}} : e^{s}

= 4 \cdot \int e^{s} d s

Use the common integral:

\int e^{s} d s = e^{s}

= 4 e^{s}

Add a constant to the solution

= 4 e^{s} + C

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