What is the integral of (3x^2-2x+2) ?

The integral of (3x^2-2x+2) is x^3-x^2+2x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (3x^2-2x+2)

\int (3 x^{2} - 2 x + 2) d x

x^{3} - x^{2} + 2 x + C

Solution steps

\int 3 x^{2} - 2 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 2 x d x + \int 2 d x

\int 3 x^{2} d x = x^{3}

\int 2 x d x = x^{2}

\int 2 d x = 2 x

= x^{3} - x^{2} + 2 x

Add a constant to the solution

= x^{3} - x^{2} + 2 x + C

\int \frac{1}{x x ^{2} - 2 ^{2}} d x

\int (y e^{x} - ln (y^{x})) d x

\int ln^{2} (\frac{1}{x}) d x

\int \frac{x + 1}{x ^{2} + x - 2} d x

\int \frac{x - 5}{( x + 4 ) ^{2}} d x

What is the integral of (3x^2-2x+2) ?
The integral of (3x^2-2x+2) is x^3-x^2+2x+C