What is (\partial)/(\partial x)(4x^2+y^2) ?

The answer to (\partial)/(\partial x)(4x^2+y^2) is 8x

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(\partial)/(\partial x)(4x^2+y^2)

\frac{\partial}{\partial x} (4 x^{2} + y^{2})

8 x

Solution steps

\frac{\partial}{\partial x} (4 x^{2} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{2}) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (4 x^{2}) = 8 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 8 x + 0

Simplify

= 8 x

y^{^{''}} - 7 y^{^{'}} = 49 t

y^{^{''}} = 9 y

\frac{\partial}{\partial y} (2 y x)

\frac{d}{d x} (\frac{- 1}{2 ( x + 1 )})

\int_{- 2}^{3} (x - 5) d x

What is (\partial)/(\partial x)(4x^2+y^2) ?
The answer to (\partial)/(\partial x)(4x^2+y^2) is 8x