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Popular >

integral of (x^2)'

Solution

\int (x^{2})^{'} d x

Solution

(x^{2})' x - x^{2} + C

Solution steps

\int (x^{2})^{'} d x

Apply Integration By Parts

: (x^{2})^{'} x - \int 2 x d x

= (x^{2})^{^{'}} x - \int 2 x d x

\int 2 x d x = x^{2}

= (x^{2})^{^{'}} x - x^{2}

Add a constant to the solution

= (x^{2})^{^{'}} x - x^{2} + C

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\int 8 (9 + x)^{5} d x

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\int (\frac{3 x + 1}{x}) d x

Frequently Asked Questions (FAQ)

What is the integral of (x^2)' ?
The integral of (x^2)' is (x^2)'x-x^2+C