What is the integral of sin^8(3/4)xcos^6(3/4)x ?

The integral of sin^8(3/4)xcos^6(3/4)x is (sin^8(3/4)cos^6(3/4)x^3)/3+C

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integral of sin^8(3/4)xcos^6(3/4)x

\int sin^{8} (\frac{3}{4}) x cos^{6} (\frac{3}{4}) x d x

\frac{sin ^{8} ( \frac{3}{4} ) cos ^{6} ( \frac{3}{4} ) x ^{3}}{3} + C

Solution steps

\int sin^{8} (\frac{3}{4}) x cos^{6} (\frac{3}{4}) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin^{8} (\frac{3}{4}) cos^{6} (\frac{3}{4}) \cdot \int xx d x

Simplify

xx : x^{2}

= sin^{8} (\frac{3}{4}) cos^{6} (\frac{3}{4}) \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= sin^{8} (\frac{3}{4}) cos^{6} (\frac{3}{4}) \frac{x ^{3}}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ^{8} ( \frac{3}{4} ) cos ^{6} ( \frac{3}{4} ) x ^{3}}{3}

Add a constant to the solution

= \frac{sin ^{8} ( \frac{3}{4} ) cos ^{6} ( \frac{3}{4} ) x ^{3}}{3} + C

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What is the integral of sin^8(3/4)xcos^6(3/4)x ?
The integral of sin^8(3/4)xcos^6(3/4)x is (sin^8(3/4)cos^6(3/4)x^3)/3+C