What is the integral of (4x-7)/((x-2)^2) ?

The integral of (4x-7)/((x-2)^2) is 4ln|x-2|-1/(x-2)+C

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integral of (4x-7)/((x-2)^2)

\int \frac{4 x - 7}{( x - 2 ) ^{2}} d x

4 ln ∣ x - 2 ∣ - \frac{1}{x - 2} + C

Solution steps

\int \frac{4 x - 7}{( x - 2 ) ^{2}} d x

Expand

\frac{4 x - 7}{( x - 2 ) ^{2}} : \frac{4 x}{( x - 2 ) ^{2}} - \frac{7}{( x - 2 ) ^{2}}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4 x}{( x - 2 ) ^{2}} d x - \int \frac{7}{( x - 2 ) ^{2}} d x

\int \frac{4 x}{( x - 2 ) ^{2}} d x = 4 (ln ∣ x - 2 ∣ - \frac{2}{x - 2})

\int \frac{7}{( x - 2 ) ^{2}} d x = - \frac{7}{x - 2}

= 4 (ln ∣ x - 2 ∣ - \frac{2}{x - 2}) - (- \frac{7}{x - 2})

Simplify

4 (ln ∣ x - 2 ∣ - \frac{2}{x - 2}) - (- \frac{7}{x - 2}) : 4 ln ∣ x - 2 ∣ - \frac{1}{x - 2}

= 4 ln ∣ x - 2 ∣ - \frac{1}{x - 2}

Add a constant to the solution

= 4 ln ∣ x - 2 ∣ - \frac{1}{x - 2} + C

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What is the integral of (4x-7)/((x-2)^2) ?
The integral of (4x-7)/((x-2)^2) is 4ln|x-2|-1/(x-2)+C