What is the derivative of x+sqrt(7x-3) ?

The derivative of x+sqrt(7x-3) is 1+7/(2sqrt(7x-3))

What is the first derivative of x+sqrt(7x-3) ?

The first derivative of x+sqrt(7x-3) is 1+7/(2sqrt(7x-3))

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\frac{d}{d x} (x + 7 x - 3)

1 + \frac{7}{2 7 x - 3}

Solution steps

\frac{d}{d x} (x + 7 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (7 x - 3)

\frac{d x}{d x} = 1

\frac{d}{d x} (7 x - 3) = \frac{7}{2 7 x - 3}

= 1 + \frac{7}{2 7 x - 3}

3 y^{^{'}} + y = 0, y^{^{'}} (0) = 0

\frac{( e ^{2 x} - 1 )}{x}

\int - x^{3} d x

\frac{d}{d y} (\frac{2 x}{y})

\frac{s - 3}{( s - 4 ) ( s + 6 )}

What is the derivative of x+sqrt(7x-3) ?
The derivative of x+sqrt(7x-3) is 1+7/(2sqrt(7x-3))
What is the first derivative of x+sqrt(7x-3) ?
The first derivative of x+sqrt(7x-3) is 1+7/(2sqrt(7x-3))