What is the integral of (sqrt(x^3)-2/(sqrt(x))) ?

The integral of (sqrt(x^3)-2/(sqrt(x))) is 2/5 x^{5/2}-4sqrt(x)+C

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integral of (sqrt(x^3)-2/(sqrt(x)))

\int (x^{3} - \frac{2}{x}) d x

\frac{2}{5} x^{\frac{5}{2}} - 4 x + C

Solution steps

\int x^{3} - \frac{2}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x - \int \frac{2}{x} d x

\int x^{3} d x = \frac{2}{5} x^{\frac{5}{2}}

\int \frac{2}{x} d x = 4 x

= \frac{2}{5} x^{\frac{5}{2}} - 4 x

Add a constant to the solution

= \frac{2}{5} x^{\frac{5}{2}} - 4 x + C

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What is the integral of (sqrt(x^3)-2/(sqrt(x))) ?
The integral of (sqrt(x^3)-2/(sqrt(x))) is 2/5 x^{5/2}-4sqrt(x)+C