What is the integral of (1-sin^2(x))/(3cos^2(x)) ?

The integral of (1-sin^2(x))/(3cos^2(x)) is 1/3 x+C

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integral of (1-sin^2(x))/(3cos^2(x))

\int \frac{1 - sin ^{2} ( x )}{3 cos ^{2} ( x )} d x

\frac{1}{3} x + C

Solution steps

\int \frac{1 - sin ^{2} ( x )}{3 cos ^{2} ( x )} d x

\frac{1 - sin ^{2} ( x )}{3 cos ^{2} ( x )} = \frac{1}{3}

= \int \frac{1}{3} d x

Integral of a constant:

\int a d x = a x

= \frac{1}{3} x

Add a constant to the solution

= \frac{1}{3} x + C

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What is the integral of (1-sin^2(x))/(3cos^2(x)) ?
The integral of (1-sin^2(x))/(3cos^2(x)) is 1/3 x+C