What is the integral of-4.15x^2+5.1x+6.096 ?

The integral of-4.15x^2+5.1x+6.096 is -1.38333…x^3+2.55x^2+6.096x+C

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integral of-4.15x^2+5.1x+6.096

\int - 4.15 x^{2} + 5.1 x + 6.096 d x

- 1.38333 \dots x^{3} + 2.55 x^{2} + 6.096 x + C

Solution steps

\int - 4.15 x^{2} + 5.1 x + 6.096 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 4.15 x^{2} d x + \int 5.1 x d x + \int 6.096 d x

\int 4.15 x^{2} d x = 1.38333 \dots x^{3}

\int 5.1 x d x = 2.55 x^{2}

\int 6.096 d x = 6.096 x

= - 1.38333 \dots x^{3} + 2.55 x^{2} + 6.096 x

Add a constant to the solution

= - 1.38333 \dots x^{3} + 2.55 x^{2} + 6.096 x + C

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What is the integral of-4.15x^2+5.1x+6.096 ?
The integral of-4.15x^2+5.1x+6.096 is -1.38333…x^3+2.55x^2+6.096x+C