What is the integral of (1-sec^2(x))/(5tan^2(x)) ?

The integral of (1-sec^2(x))/(5tan^2(x)) is -1/5 x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (1-sec^2(x))/(5tan^2(x))

\int \frac{1 - sec ^{2} ( x )}{5 tan ^{2} ( x )} d x

- \frac{1}{5} x + C

Solution steps

\int \frac{1 - sec ^{2} ( x )}{5 tan ^{2} ( x )} d x

\frac{1 - sec ^{2} ( x )}{5 tan ^{2} ( x )} = - \frac{1}{5}

= \int - \frac{1}{5} d x

Integral of a constant:

\int a d x = a x

= (- \frac{1}{5}) x

Simplify

= - \frac{1}{5} x

Add a constant to the solution

= - \frac{1}{5} x + C

\int \frac{1}{sin ^{5} ( x ) \cdot cos ( x )} d x

\int \frac{x ^{2}}{1 + y ^{2}} d y

\int \frac{4 x ^{3}}{( 2 - x ^{4} ) ^{6}} d x

\int \frac{1}{10} e^{- \frac{1}{10} x} d x

\int cos (e x) d x

What is the integral of (1-sec^2(x))/(5tan^2(x)) ?
The integral of (1-sec^2(x))/(5tan^2(x)) is -1/5 x+C