What is the integral of (3x^3+4x-3) ?

The integral of (3x^3+4x-3) is (3x^4)/4+2x^2-3x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (3x^3+4x-3)

\int (3 x^{3} + 4 x - 3) d x

\frac{3 x ^{4}}{4} + 2 x^{2} - 3 x + C

Solution steps

\int 3 x^{3} + 4 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{3} d x + \int 4 x d x - \int 3 d x

\int 3 x^{3} d x = \frac{3 x ^{4}}{4}

\int 4 x d x = 2 x^{2}

\int 3 d x = 3 x

= \frac{3 x ^{4}}{4} + 2 x^{2} - 3 x

Add a constant to the solution

= \frac{3 x ^{4}}{4} + 2 x^{2} - 3 x + C

\int \frac{3}{( x + 1 ) ^{3}} d x

\int \frac{x ( x + 2 )}{x ^{3} + 3 x ^{2} + 1} d x

\int \frac{2 ^{x}}{7 ^{x}} d x

\int (sin (x^{3}) x^{2} + ln (x)) d x

\int \frac{x ^{2} + 1}{x ^{3} - x ^{2}} d x

What is the integral of (3x^3+4x-3) ?
The integral of (3x^3+4x-3) is (3x^4)/4+2x^2-3x+C