What is the integral of (2x^3-3x+2) ?

The integral of (2x^3-3x+2) is (x^4)/2-(3x^2)/2+2x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2x^3-3x+2)

\int (2 x^{3} - 3 x + 2) d x

\frac{x ^{4}}{2} - \frac{3 x ^{2}}{2} + 2 x + C

Solution steps

\int 2 x^{3} - 3 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{3} d x - \int 3 x d x + \int 2 d x

\int 2 x^{3} d x = \frac{x ^{4}}{2}

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 2 d x = 2 x

= \frac{x ^{4}}{2} - \frac{3 x ^{2}}{2} + 2 x

Add a constant to the solution

= \frac{x ^{4}}{2} - \frac{3 x ^{2}}{2} + 2 x + C

\int \frac{14 x ^{2}}{x ^{4} - 25 x ^{2} + 144} d x

\int \frac{sin ^{3} ( y )}{1 + cos ( y )} d y

\int \frac{cot ^{2} ( t )}{csc ( t )} d t

\int \frac{x ^{2} - 4}{x ^{2} - 16} d x

\int \frac{1}{x ^{0.99}} d x

What is the integral of (2x^3-3x+2) ?
The integral of (2x^3-3x+2) is (x^4)/2-(3x^2)/2+2x+C