What is the integral of 0.024*(0.03q^2-2q)+130 ?

The integral of 0.024*(0.03q^2-2q)+130 is 0.024(0.01q^3-q^2)+130q+C

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integral of 0.024*(0.03q^2-2q)+130

\int 0.024 \cdot (0.03 q^{2} - 2 q) + 130 d q

0.024 (0.01 q^{3} - q^{2}) + 130 q + C

Solution steps

\int 0.024 (0.03 q^{2} - 2 q) + 130 d q

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.024 (0.03 q^{2} - 2 q) d q + \int 130 d q

\int 0.024 (0.03 q^{2} - 2 q) d q = 0.024 (0.01 q^{3} - q^{2})

\int 130 d q = 130 q

= 0.024 (0.01 q^{3} - q^{2}) + 130 q

Add a constant to the solution

= 0.024 (0.01 q^{3} - q^{2}) + 130 q + C

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What is the integral of 0.024*(0.03q^2-2q)+130 ?
The integral of 0.024*(0.03q^2-2q)+130 is 0.024(0.01q^3-q^2)+130q+C