What is area y=13+2x-x^2,y=3x+1 ?

The answer to area y=13+2x-x^2,y=3x+1 is 343/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=13+2x-x^2,y=3x+1

area

y = 13 + 2 x - x^{2}, y = 3 x + 1

\frac{343}{6}

Decimal Notation

57.16666 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{3} 13 + 2 x - x^{2} - (3 x + 1) d x

Solve

\int_{- 4}^{3} 13 + 2 x - x^{2} - (3 x + 1) d x : \frac{343}{6}

The area is:

= \frac{343}{6}

\int \frac{x ^{4}}{1 + x ^{2}} d x

\frac{d}{d x} (\frac{x ^{4}}{4} + \frac{8}{9} x^{3} - x^{2} + 3 x - 8)

x \to - 8 lim (\frac{∣ x - 8 ∣}{x - 8})

x \to 0 lim (\frac{x ^{3}}{3})

\frac{d}{d x} (- 5 x^{4})

What is area y=13+2x-x^2,y=3x+1 ?
The answer to area y=13+2x-x^2,y=3x+1 is 343/6