What is the integral of (-y)/(x^2) ?

The integral of (-y)/(x^2) is y/x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (-y)/(x^2)

\int \frac{- y}{x ^{2}} d x

\frac{y}{x} + C

Solution steps

\int \frac{- y}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - y \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - y (- \frac{1}{x})

Simplify

- y (- \frac{1}{x}) : \frac{y}{x}

= \frac{y}{x}

Add a constant to the solution

= \frac{y}{x} + C

\int (x^{2} - \frac{1}{x ^{2}})^{2} d x

\int sin^{4} (7 x) cos (7 x) d x

\int \frac{7 x}{x ^{2} + 14 x + 40} d x

\int (1 + y + e^{y}) d y

\int x^{2} sin (2 x + 5) d x