What is the integral of (e^{2x})/(sqrt(7-4e^{2x))} ?

The integral of (e^{2x})/(sqrt(7-4e^{2x))} is -1/4 sqrt(7-4e^{2x)}+C

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integral of (e^{2x})/(sqrt(7-4e^{2x))}

\int \frac{e ^{2 x}}{7 - 4 e ^{2 x}} d x

- \frac{1}{4} 7 - 4 e^{2 x} + C

Solution steps

\int \frac{e ^{2 x}}{7 - 4 e ^{2 x}} d x

Apply u-substitution

: \int - \frac{1}{8 u} d u

= \int - \frac{1}{8 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{8} \cdot \int \frac{1}{u} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= - \frac{1}{8} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = 7 - 4 e^{2 x}

= - \frac{1}{8} \cdot 2 (7 - 4 e^{2 x})^{\frac{1}{2}}

Simplify

- \frac{1}{8} \cdot 2 (7 - 4 e^{2 x})^{\frac{1}{2}} : - \frac{1}{4} 7 - 4 e^{2 x}

= - \frac{1}{4} 7 - 4 e^{2 x}

Add a constant to the solution

= - \frac{1}{4} 7 - 4 e^{2 x} + C

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What is the integral of (e^{2x})/(sqrt(7-4e^{2x))} ?
The integral of (e^{2x})/(sqrt(7-4e^{2x))} is -1/4 sqrt(7-4e^{2x)}+C