What is the limit as h approaches 0 of tan(h) ?

The limit as h approaches 0 of tan(h) is 0

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limit as h approaches 0 of tan(h)

h \to 0 lim (tan (h))

0

Solution steps

h \to 0 lim (tan (h))

Plug in the value

h = 0

= tan (0)

Use the following trivial identity:

tan (0) = 0

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 0

\frac{d}{d t} (t e^{2 t})

\int (x + 1) e^{5 x^{2} + 10 x} d x

(1 + 9 x^{2}) (x - x^{2})

\frac{d}{d x} (7 x (sin (x) + cos (x)))

\frac{d x}{d t} = 2 e^{t} - 2

What is the limit as h approaches 0 of tan(h) ?
The limit as h approaches 0 of tan(h) is 0