What is the integral of x^2cos^2(x ?

The integral of x^2cos^2(x is (x^4cos^2(d))/4+C

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integral of x^2cos^2(x

\int x^{2} cos^{2} (d) x d x

\frac{x ^{4} cos ^{2} ( d )}{4} + C

Solution steps

\int x^{2} cos^{2} (d) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= cos^{2} (d) \cdot \int x^{2} x d x

Simplify

x^{2} x : x^{3}

= cos^{2} (d) \cdot \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= cos^{2} (d) \frac{x ^{4}}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x ^{4} cos ^{2} ( d )}{4}

Add a constant to the solution

= \frac{x ^{4} cos ^{2} ( d )}{4} + C

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What is the integral of x^2cos^2(x ?
The integral of x^2cos^2(x is (x^4cos^2(d))/4+C