What is the integral of (6x^{-2}+10) ?

The integral of (6x^{-2}+10) is -6/x+10x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (6x^{-2}+10)

\int (6 x^{- 2} + 10) d x

- \frac{6}{x} + 10 x + C

Solution steps

\int 6 x^{- 2} + 10 d x

6 x^{- 2} = \frac{6}{x ^{2}}

= \int \frac{6}{x ^{2}} + 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{6}{x ^{2}} d x + \int 10 d x

\int \frac{6}{x ^{2}} d x = - \frac{6}{x}

\int 10 d x = 10 x

= - \frac{6}{x} + 10 x

Add a constant to the solution

= - \frac{6}{x} + 10 x + C

\int 6 tan (x) d x

\int \frac{sin ( 3 t )}{cos ( 3 t ) - 1} d t

\int \frac{x}{( 2 x + 1 ) ^{\frac{1}{2}}} d x

\int - 6 cos (3 x) + 5 sin (7 x) d x

\int x x^{2} - a d x

What is the integral of (6x^{-2}+10) ?
The integral of (6x^{-2}+10) is -6/x+10x+C