What is the integral of (4x^3+6x+10) ?

The integral of (4x^3+6x+10) is x^4+3x^2+10x+C

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integral of (4x^3+6x+10)

\int (4 x^{3} + 6 x + 10) d x

x^{4} + 3 x^{2} + 10 x + C

Solution steps

\int 4 x^{3} + 6 x + 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{3} d x + \int 6 x d x + \int 10 d x

\int 4 x^{3} d x = x^{4}

\int 6 x d x = 3 x^{2}

\int 10 d x = 10 x

= x^{4} + 3 x^{2} + 10 x

Add a constant to the solution

= x^{4} + 3 x^{2} + 10 x + C

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What is the integral of (4x^3+6x+10) ?
The integral of (4x^3+6x+10) is x^4+3x^2+10x+C