What is the integral of cos(3x+10) ?

The integral of cos(3x+10) is 1/3 sin(3x+10)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of cos(3x+10)

\int cos (3 x + 10) d x

\frac{1}{3} sin (3 x + 10) + C

Solution steps

\int cos (3 x + 10) d x

Apply u-substitution

: \int cos (u) \frac{1}{3} d u

= \int cos (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{3} sin (u)

Substitute back

u = 3 x + 10

= \frac{1}{3} sin (3 x + 10)

Add a constant to the solution

= \frac{1}{3} sin (3 x + 10) + C

\int (x^{2} + 4 x) x^{3} + 6 x^{2} + 1 d x

\int 4 x y x^{2} + y^{2} d y

\int \frac{2 t - 1}{t ^{2} - t + 2} d t

\int (1 - y)^{2} d y

\int \frac{1}{7 - x ^{2}} d x

What is the integral of cos(3x+10) ?
The integral of cos(3x+10) is 1/3 sin(3x+10)+C