What is the integral of (cos(β))/(2+3sin(β)) ?

The integral of (cos(β))/(2+3sin(β)) is 1/3 ln|2+3sin(β)|+C

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integral of (cos(β))/(2+3sin(β))

\int \frac{cos ( β )}{2 + 3 sin ( β )} d β

\frac{1}{3} ln ∣ 2 + 3 sin (β) ∣ + C

Solution steps

\int \frac{cos ( β )}{2 + 3 sin ( β )} d β

Apply u-substitution

: \int \frac{1}{3 u} d u

= \int \frac{1}{3 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{3} ln ∣ u ∣

Substitute back

u = 2 + 3 sin (β)

= \frac{1}{3} ln ∣ 2 + 3 sin (β) ∣

Add a constant to the solution

= \frac{1}{3} ln ∣ 2 + 3 sin (β) ∣ + C

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What is the integral of (cos(β))/(2+3sin(β)) ?
The integral of (cos(β))/(2+3sin(β)) is 1/3 ln|2+3sin(β)|+C