What is the integral of x^2sin(b)x ?

The integral of x^2sin(b)x is 1/4 x^4sin(b)+C

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integral of x^2sin(b)x

\int x^{2} sin (b) x d x

\frac{1}{4} x^{4} sin (b) + C

Solution steps

\int x^{2} sin (b) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin (b) \cdot \int x^{2} x d x

Simplify

x^{2} x : x^{3}

= sin (b) \cdot \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= sin (b) \frac{x ^{4}}{4}

Simplify

sin (b) \frac{x ^{4}}{4} : \frac{1}{4} x^{4} sin (b)

= \frac{1}{4} x^{4} sin (b)

Add a constant to the solution

= \frac{1}{4} x^{4} sin (b) + C

\int 3 x^{3} e^{4 x} d x

\int 6 t + t sin (t^{2} + 1) d t

\int sec^{2} (3 x) + tan (6 x) d x

\int t^{4} cos (t^{5}) d t

What is the integral of x^2sin(b)x ?
The integral of x^2sin(b)x is 1/4 x^4sin(b)+C