What is the integral of 1/(sqrt(1-θ)) ?

The integral of 1/(sqrt(1-θ)) is -2sqrt(1-θ)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(sqrt(1-θ))

\int \frac{1}{1 - θ} d θ

- 2 1 - θ + C

Solution steps

\int \frac{1}{1 - θ} d θ

Apply u-substitution

: \int - \frac{1}{u} d u

= \int - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{u} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= - 2 u^{\frac{1}{2}}

Substitute back

u = 1 - θ

= - 2 (1 - θ)^{\frac{1}{2}}

Apply radical rule:

= - 2 1 - θ

Add a constant to the solution

= - 2 1 - θ + C

\int (x^{2} - 2 x + 5) cos (3 x) d x

\int \frac{5 x ^{3} + 7 x ^{2} - 2 x - 4}{x ^{3} - x ^{2}} d x

\int \frac{x}{( x - 1 ) ( x - 4 ) ( x - 1 )} d x

\int \frac{7}{( 2 x + 1 ) [ 1 + ln ( 2 x + 1 ) ] ^{2}} d x

What is the integral of 1/(sqrt(1-θ)) ?
The integral of 1/(sqrt(1-θ)) is -2sqrt(1-θ)+C