What is the integral of (cos(2x)+1)/2 ?

The integral of (cos(2x)+1)/2 is 1/2 (1/2 sin(2x)+x)+C

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integral of (cos(2x)+1)/2

\int \frac{cos ( 2 x ) + 1}{2} d x

\frac{1}{2} (\frac{1}{2} sin (2 x) + x) + C

Solution steps

\int \frac{cos ( 2 x ) + 1}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int cos (2 x) + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int cos (2 x) d x + \int 1 d x)

\int cos (2 x) d x = \frac{1}{2} sin (2 x)

\int 1 d x = x

= \frac{1}{2} (\frac{1}{2} sin (2 x) + x)

Add a constant to the solution

= \frac{1}{2} (\frac{1}{2} sin (2 x) + x) + C

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What is the integral of (cos(2x)+1)/2 ?
The integral of (cos(2x)+1)/2 is 1/2 (1/2 sin(2x)+x)+C