What is the integral of e^{-e^{-x}-x} ?

The integral of e^{-e^{-x}-x} is e^{-e^{-x}}+C

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integral of e^{-e^{-x}-x}

\int e^{- e^{- x} - x} d x

e^{- e^{- x}} + C

Solution steps

\int e^{- e^{- x} - x} d x

Apply u-substitution

: \int - e^{- u} d u

= \int - e^{- u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int e^{- u} d u

Apply u-substitution

: \int - e^{v} d v

= - \int - e^{v} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int e^{v} d v)

Use the common integral:

\int e^{v} d v = e^{v}

= - (- e^{v})

Substitute back

= - (- e^{- e^{- x}})

Simplify

= e^{- e^{- x}}

Add a constant to the solution

= e^{- e^{- x}} + C

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What is the integral of e^{-e^{-x}-x} ?
The integral of e^{-e^{-x}-x} is e^{-e^{-x}}+C