What is the integral of+sqrt(cos(θ))sin^3(θ) ?

The integral of+sqrt(cos(θ))sin^3(θ) is -2/3 cos^{3/2}(θ)+2/7 cos^{7/2}(θ)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of+sqrt(cos(θ))sin^3(θ)

\int + cos (θ) sin^{3} (θ) d θ

- \frac{2}{3} cos^{\frac{3}{2}} (θ) + \frac{2}{7} cos^{\frac{7}{2}} (θ) + C

Solution steps

\int cos (θ) sin^{3} (θ) d θ

Apply u-substitution

: \int - u (1 - u^{2}) d u

= \int - u (1 - u^{2}) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u (1 - u^{2}) d u

Expand

u (1 - u^{2}) : u - u^{\frac{5}{2}}

= - \int u - u^{\frac{5}{2}} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (\int u d u - \int u^{\frac{5}{2}} d u)

\int u d u = \frac{2}{3} u^{\frac{3}{2}}

\int u^{\frac{5}{2}} d u = \frac{2}{7} u^{\frac{7}{2}}

= - (\frac{2}{3} u^{\frac{3}{2}} - \frac{2}{7} u^{\frac{7}{2}})

Substitute back

u = cos (θ)

= - (\frac{2}{3} cos^{\frac{3}{2}} (θ) - \frac{2}{7} cos^{\frac{7}{2}} (θ))

Simplify

= - \frac{2}{3} cos^{\frac{3}{2}} (θ) + \frac{2}{7} cos^{\frac{7}{2}} (θ)

Add a constant to the solution

= - \frac{2}{3} cos^{\frac{3}{2}} (θ) + \frac{2}{7} cos^{\frac{7}{2}} (θ) + C

\int e^{x} (1 - x^{2}) d x

\int (3 - 2 x) (1 + x^{2}) x d x

\int \frac{3 x + 4}{4 - x ^{2}} d x

\int \frac{x ^{2} - 15}{x ^{3}} d x

\int \frac{4 x - 2}{x ^{3} - x} d x

What is the integral of+sqrt(cos(θ))sin^3(θ) ?
The integral of+sqrt(cos(θ))sin^3(θ) is -2/3 cos^{3/2}(θ)+2/7 cos^{7/2}(θ)+C