What is the integral of 8-4\sqrt[3]{x} ?

The integral of 8-4\sqrt[3]{x} is 8x-3x^{4/3}+C

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integral of 8-4\sqrt[3]{x}

8 x - 3 x^{\frac{4}{3}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 8 d x = 8 x

= 8 x - 3 x^{\frac{4}{3}}

Add a constant to the solution

= 8 x - 3 x^{\frac{4}{3}} + C

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What is the integral of 8-4\sqrt[3]{x} ?
The integral of 8-4\sqrt[3]{x} is 8x-3x^{4/3}+C