What is the integral of sqrt(1/(x+1)) ?

The integral of sqrt(1/(x+1)) is 2sqrt(x+1)+C

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integral of sqrt(1/(x+1))

\int \frac{1}{x + 1} d x

2 x + 1 + C

Solution steps

\int \frac{1}{x + 1} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Simplify

\frac{1}{u} : \frac{1}{u}

= \int \frac{1}{u} d u

Simplify

= \int \frac{1}{u} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= 2 u^{\frac{1}{2}}

Substitute back

u = x + 1

= 2 (x + 1)^{\frac{1}{2}}

Apply radical rule:

= 2 x + 1

Add a constant to the solution

= 2 x + 1 + C

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What is the integral of sqrt(1/(x+1)) ?
The integral of sqrt(1/(x+1)) is 2sqrt(x+1)+C