What is area f(x)=4-(x-1)^2,(1,3) ?

The answer to area f(x)=4-(x-1)^2,(1,3) is 16/3

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area f(x)=4-(x-1)^2,(1,3)

area

f (x) = 4 - (x - 1)^{2}, (1, 3)

\frac{16}{3}

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{1}^{3} 4 - (x - 1)^{2} d x

Solve

\int_{1}^{3} 4 - (x - 1)^{2} d x : \frac{16}{3}

The area is:

= \frac{16}{3}

n = 0 \sum \infty (- \frac{x}{4})^{n}

f (x) = ln (6 - 9 x^{2} + 8 x^{4}), at x = 1

\int \frac{r ^{3}}{4 - r ^{2}} d r

y = \frac{9}{x - 5} - 1

\int \frac{x}{x ^{4} + 4} d x

What is area f(x)=4-(x-1)^2,(1,3) ?
The answer to area f(x)=4-(x-1)^2,(1,3) is 16/3