What is the integral of tan^2(x)+cot^2(x) ?

The integral of tan^2(x)+cot^2(x) is -2x+tan(x)-cot(x)+C

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integral of tan^2(x)+cot^2(x)

\int tan^{2} (x) + cot^{2} (x) d x

- 2 x + tan (x) - cot (x) + C

Solution steps

\int tan^{2} (x) + cot^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int tan^{2} (x) d x + \int cot^{2} (x) d x

\int tan^{2} (x) d x = - x + tan (x)

\int cot^{2} (x) d x = - x - cot (x)

= - x + tan (x) - x - cot (x)

Simplify

= - 2 x + tan (x) - cot (x)

Add a constant to the solution

= - 2 x + tan (x) - cot (x) + C

\int \frac{3 x ^{2}}{cos ^{2} ( x ^{3} )} d x

\int (3 x + y) d y

\int \frac{8}{5 x 25 x ^{2} - 25} d x

\int x (x^{3} + 2)^{2} d x

\frac{1}{( x + 3 )}

What is the integral of tan^2(x)+cot^2(x) ?
The integral of tan^2(x)+cot^2(x) is -2x+tan(x)-cot(x)+C