What is the integral of (3/(sqrt(x+1))) ?

The integral of (3/(sqrt(x+1))) is 6sqrt(x+1)+C

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integral of (3/(sqrt(x+1)))

\int (\frac{3}{x + 1}) d x

6 x + 1 + C

Solution steps

\int \frac{3}{x + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{x + 1} d x

Apply u-substitution

: \int 2 d u

= 3 \cdot \int 2 d u

Integral of a constant:

\int a d x = a x

= 3 \cdot 2 u

Substitute back

u = x + 1

= 3 \cdot 2 x + 1

Simplify

= 6 x + 1

Add a constant to the solution

= 6 x + 1 + C

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What is the integral of (3/(sqrt(x+1))) ?
The integral of (3/(sqrt(x+1))) is 6sqrt(x+1)+C