What is the integral of cos(13-2y) ?

The integral of cos(13-2y) is -1/2 sin(13-2y)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of cos(13-2y)

\int cos (13 - 2 y) d y

- \frac{1}{2} sin (13 - 2 y) + C

Solution steps

\int cos (13 - 2 y) d y

Apply u-substitution

: \int - \frac{1}{2} cos (u) d u

= \int - \frac{1}{2} cos (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= - \frac{1}{2} sin (u)

Substitute back

u = 13 - 2 y

= - \frac{1}{2} sin (13 - 2 y)

Add a constant to the solution

= - \frac{1}{2} sin (13 - 2 y) + C

\int \frac{x ^{3}}{( x + 1 ) ^{4}} d x

\int sin^{5} (x) \cdot cos^{6} (x) d x

\int \frac{x - 2 x}{x ^{3}} d x

\int \frac{3 x + 4}{x ^{3} - 2 x - 4} d x

What is the integral of cos(13-2y) ?
The integral of cos(13-2y) is -1/2 sin(13-2y)+C