What is the integral of e^{(ax+b)} ?

The integral of e^{(ax+b)} is 1/a e^{ax+b}+C

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integral of e^{(ax+b)}

\int e^{(a x + b)} d x

\frac{1}{a} e^{a x + b} + C

Solution steps

\int e^{a x + b} d x

Apply u-substitution

: \int \frac{e ^{u}}{a} d u

= \int \frac{e ^{u}}{a} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{a} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{a} e^{u}

Substitute back

u = a x + b

= \frac{1}{a} e^{a x + b}

Add a constant to the solution

= \frac{1}{a} e^{a x + b} + C

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What is the integral of e^{(ax+b)} ?
The integral of e^{(ax+b)} is 1/a e^{ax+b}+C