What is the integral of (e^x*cos(e^x)) ?

The integral of (e^x*cos(e^x)) is sin(e^x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (e^x*cos(e^x))

\int (e^{x} \cdot cos (e^{x})) d x

sin (e^{x}) + C

Solution steps

\int e^{x} cos (e^{x}) d x

Apply u-substitution

: \int cos (u) d u

= \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= sin (u)

Substitute back

u = e^{x}

= sin (e^{x})

Add a constant to the solution

= sin (e^{x}) + C

\int (2 x - \frac{1}{x})^{2} d x

\int \frac{ln ( x )}{( ln ( x ) + 1 ) ^{2}} d x

\int \frac{z ^{4} - 3 z ^{2} - 4 z}{6 z} d z

\int \frac{4 x ^{2}}{9 - x ^{2}} d x

\int \frac{( 1 + ln ( x ) ) ^{2}}{x} d x

What is the integral of (e^x*cos(e^x)) ?
The integral of (e^x*cos(e^x)) is sin(e^x)+C