What is the integral of cos^2(1/2)y ?

The integral of cos^2(1/2)y is (cos^2(1/2)y^2)/2+C

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integral of cos^2(1/2)y

\int cos^{2} (\frac{1}{2}) y d y

\frac{cos ^{2} ( \frac{1}{2} ) y ^{2}}{2} + C

Solution steps

\int cos^{2} (\frac{1}{2}) y d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= cos^{2} (\frac{1}{2}) \cdot \int y d y

Apply the Power Rule

: \frac{y ^{2}}{2}

= cos^{2} (\frac{1}{2}) \frac{y ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{cos ^{2} ( \frac{1}{2} ) y ^{2}}{2}

Add a constant to the solution

= \frac{cos ^{2} ( \frac{1}{2} ) y ^{2}}{2} + C

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What is the integral of cos^2(1/2)y ?
The integral of cos^2(1/2)y is (cos^2(1/2)y^2)/2+C