What is the integral of 3/(\sqrt[3]{y)} ?

The integral of 3/(\sqrt[3]{y)} is 9/2 y^{2/3}+C

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integral of 3/(\sqrt[3]{y)}

\int \frac{3}{3 y} d y

\frac{9}{2} y^{\frac{2}{3}} + C

Solution steps

\int \frac{3}{3 y} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{3 y} d y

Apply the Power Rule

: \frac{3}{2} y^{\frac{2}{3}}

= 3 \cdot \frac{3}{2} y^{\frac{2}{3}}

Simplify

3 \cdot \frac{3}{2} y^{\frac{2}{3}} : \frac{9}{2} y^{\frac{2}{3}}

= \frac{9}{2} y^{\frac{2}{3}}

Add a constant to the solution

= \frac{9}{2} y^{\frac{2}{3}} + C

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What is the integral of 3/(\sqrt[3]{y)} ?
The integral of 3/(\sqrt[3]{y)} is 9/2 y^{2/3}+C