What is the integral of 1/x+1/(1-x) ?

The integral of 1/x+1/(1-x) is ln|x|-ln|1-x|+C

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integral of 1/x+1/(1-x)

\int \frac{1}{x} + \frac{1}{1 - x} d x

ln ∣ x ∣ - ln ∣ 1 - x ∣ + C

Solution steps

\int \frac{1}{x} + \frac{1}{1 - x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x + \int \frac{1}{1 - x} d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int \frac{1}{1 - x} d x = - ln ∣ 1 - x ∣

= ln ∣ x ∣ - ln ∣ 1 - x ∣

Add a constant to the solution

= ln ∣ x ∣ - ln ∣ 1 - x ∣ + C

\int \frac{x ^{3}}{x ^{3} - x} d x

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\int (2 x - 6) d x

What is the integral of 1/x+1/(1-x) ?
The integral of 1/x+1/(1-x) is ln|x|-ln|1-x|+C