What is the integral of (2x^2-x+3) ?

The integral of (2x^2-x+3) is (2x^3)/3-(x^2)/2+3x+C

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integral of (2x^2-x+3)

\int (2 x^{2} - x + 3) d x

\frac{2 x ^{3}}{3} - \frac{x ^{2}}{2} + 3 x + C

Solution steps

\int 2 x^{2} - x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x - \int x d x + \int 3 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int x d x = \frac{x ^{2}}{2}

\int 3 d x = 3 x

= \frac{2 x ^{3}}{3} - \frac{x ^{2}}{2} + 3 x

Add a constant to the solution

= \frac{2 x ^{3}}{3} - \frac{x ^{2}}{2} + 3 x + C

\int \frac{x ^{2} - x + 5}{x + 3} d x

\int \frac{x - x ^{- 3}}{x ^{2} + x ^{- 2}} d x

\int (3 x^{2} + 4 x - 5) d x

\int \frac{2 x - 5}{x ^{2} - 5 x + 3} d x

\int 12 x - 3 d x

What is the integral of (2x^2-x+3) ?
The integral of (2x^2-x+3) is (2x^3)/3-(x^2)/2+3x+C