What is the integral of x^3-0.3x^2-8.56x+8.448 ?

The integral of x^3-0.3x^2-8.56x+8.448 is 0.25x^4-0.1x^3-4.28x^2+8.448x+C

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integral of x^3-0.3x^2-8.56x+8.448

\int x^{3} - 0.3 x^{2} - 8.56 x + 8.448 d x

0.25 x^{4} - 0.1 x^{3} - 4.28 x^{2} + 8.448 x + C

Solution steps

\int x^{3} - 0.3 x^{2} - 8.56 x + 8.448 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x - \int 0.3 x^{2} d x - \int 8.56 x d x + \int 8.448 d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 0.3 x^{2} d x = 0.1 x^{3}

\int 8.56 x d x = 4.28 x^{2}

\int 8.448 d x = 8.448 x

= \frac{x ^{4}}{4} - 0.1 x^{3} - 4.28 x^{2} + 8.448 x

Simplify

= 0.25 x^{4} - 0.1 x^{3} - 4.28 x^{2} + 8.448 x

Add a constant to the solution

= 0.25 x^{4} - 0.1 x^{3} - 4.28 x^{2} + 8.448 x + C

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What is the integral of x^3-0.3x^2-8.56x+8.448 ?
The integral of x^3-0.3x^2-8.56x+8.448 is 0.25x^4-0.1x^3-4.28x^2+8.448x+C