What is the integral of e^{3p-7} ?

The integral of e^{3p-7} is 1/3 e^{3p-7}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{3p-7}

\int e^{3 p - 7} d p

\frac{1}{3} e^{3 p - 7} + C

Solution steps

\int e^{3 p - 7} d p

Apply u-substitution

: \int e^{u} \frac{1}{3} d u

= \int e^{u} \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{3} e^{u}

Substitute back

u = 3 p - 7

= \frac{1}{3} e^{3 p - 7}

Add a constant to the solution

= \frac{1}{3} e^{3 p - 7} + C

\int \frac{x ^{5} + 3}{x ^{2} - 3 x + 2} d x

\int \frac{6 x + 5}{x ^{2} + 1} d x

\int (x^{7} + 2)^{2} d x

\int \frac{5 x - 23}{x ^{2} - 9 x + 20} d x

\int \frac{1}{2 x} sin (x) d x