What is the integral of (e^{3x-4}) ?

The integral of (e^{3x-4}) is 1/3 e^{3x-4}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (e^{3x-4})

\int (e^{3 x - 4}) d x

\frac{1}{3} e^{3 x - 4} + C

Solution steps

\int e^{3 x - 4} d x

Apply u-substitution

: \int e^{u} \frac{1}{3} d u

= \int e^{u} \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{3} e^{u}

Substitute back

u = 3 x - 4

= \frac{1}{3} e^{3 x - 4}

Add a constant to the solution

= \frac{1}{3} e^{3 x - 4} + C

\int (4 + x^{2})^{\frac{3}{2}} d x

\int \frac{e ^{- x} cosh ( x )}{2} d x

\int \frac{1}{2 - e ^{x}} d x

\int \frac{( x ^{4} - 1 )}{x ^{2} ( x + 1 ) ^{2}} d x

\int \frac{1}{( 1 + x + y + z ) ^{3}} d z

What is the integral of (e^{3x-4}) ?
The integral of (e^{3x-4}) is 1/3 e^{3x-4}+C