What is the integral of (16)/(x^3) ?

The integral of (16)/(x^3) is -8/(x^2)+C

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integral of (16)/(x^3)

\int \frac{16}{x ^{3}} d x

- \frac{8}{x ^{2}} + C

Solution steps

\int \frac{16}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 16 \cdot \int \frac{1}{x ^{3}} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= 16 (- \frac{1}{2 x ^{2}})

Simplify

16 (- \frac{1}{2 x ^{2}}) : - \frac{8}{x ^{2}}

= - \frac{8}{x ^{2}}

Add a constant to the solution

= - \frac{8}{x ^{2}} + C

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