What is the integral of c/(1+x^2) ?

The integral of c/(1+x^2) is carctan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of c/(1+x^2)

\int \frac{c}{1 + x ^{2}} d x

c arctan (x) + C

Solution steps

\int \frac{c}{1 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= c \cdot \int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= c arctan (x)

Add a constant to the solution

= c arctan (x) + C

\int \frac{x}{z ^{2} + x ^{2}} d x

\int sec (\frac{t}{3}) d t

\int 90 e^{- 0.12 x} d x

\int \frac{( 2 x + 3 )}{4 x ^{2} + 4 x + 5} d x

\int \frac{18 s + 18}{( s ^{2} + 1 ) ( s - 1 ) ^{3}} d s